in an isosceles triangle the base angle is twice as large as vertex angle find angle of triangle
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An isosceles triangle has two sides of equal length. Likewise, the opposite angles of the sides are the same
So lets assume each angle be x and the bigger angle be 2x (since it is twice the base angle)
Now, we know that sum of the angles in a triangle is 180 degree
So,
→2x+x+x=180∘
→4x=180∘
→x=1804
⇒x=45∘
Now the other angle is 2x which is 45×2=90
So lets assume each angle be x and the bigger angle be 2x (since it is twice the base angle)
Now, we know that sum of the angles in a triangle is 180 degree
So,
→2x+x+x=180∘
→4x=180∘
→x=1804
⇒x=45∘
Now the other angle is 2x which is 45×2=90
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