In an isosceles triangle ,the base angle is twice as large as vertex angle . Find the angles of a triangle .
Answers
Answered by
70
Let the angle at the vertex be x.
Therefore the base angles are 2x each(as isosceles triangle).
2x+2x+x= 180(Angle sum property)
5x = 180
x = 180/5
x = 36.
There fore the angles are 30° , 72°, 72°
Answered by
37
Let the vertex angle 'A' =x then base angle 'B' =2x
We know in isoceles triangle opposite angles are equal
So both base angle 'C' is also = to 2x
Therefore all angles are
X , 2x , 2x
Sum of all angles in teiangle is 180
So , x+2x+2x =180
5x =180
×=180/5
X = 36
2x= 2×36
=72
Therefore all angles are 36 , 72 and 72
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