in an isosceles triangle, the base angle is twice as large as vertex angle. find the angles of the triangle.
MazharulIslam:
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2x and x
is the answer
is the answer
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let the vertex angle be x.
then,base =2x
Since we know that ,vertex angles are equal
So,x+2x+x=180(angle sum property of a triangle)
or,4x=180
or,x=180/4=45
vertex angle=45°each
base angle =45×2=90°
then,base =2x
Since we know that ,vertex angles are equal
So,x+2x+x=180(angle sum property of a triangle)
or,4x=180
or,x=180/4=45
vertex angle=45°each
base angle =45×2=90°
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By the way your ANSWER is wrong
the ANSWER is 70
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