in an isosceles triangle, the base angle is twice as large as vertex angle. Find the angles of the triangle
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let the vertex angle be x
base angle= 2x
2x+2x+x=180
5x=180
x=180/5
x=36
other two angles are 2x=36×2=72
angles are72,72,36
pls mark me as brainliest
base angle= 2x
2x+2x+x=180
5x=180
x=180/5
x=36
other two angles are 2x=36×2=72
angles are72,72,36
pls mark me as brainliest
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