Math, asked by Alonmolsom, 11 months ago

In an isosceles triangle, the base angles are equal . the vertex angle is 40°. what are the base angles of the triangle?​

Answers

Answered by brunoconti
5

Answer:

Step-by-step explanation:

A + B + C = 180°

A = 40° and B = C

40 + 2B = 180

2B = 140

B = C = 70°

Answered by ayushjain2212
1

Answer:

Base angels are :- 70°

Step-by-step explanation:

in isosceles triangle two sides have equal length And two equal angle

let the equal angles be x°

sum of all the angels of triangle is 180°

therefore, x°+x°+40°=180°

2x°+40°=180°

2x°=180° - 40°

2x°=140°

x°=140°/2°

x°=70°

Similar questions