Math, asked by siddharthasingh35, 10 months ago

In an isosceles triangle, the base angles are equal. The vertex angle is 40°. What are the base angles of the triangle? (Remember, the sum of three angles of a triangle is 180°)​

Answers

Answered by bangarijaya81
7

Answer:

(sum of all sides of triangle =180)

only two sides of isosceles triangle are equal.

so angle A+B+C=180

angleA=40

angleB=X

angle C=X

so180-40=140

140/2=70

angle a=40

angle b =70

angle c=70

Answered by Anonymous
0

Answer:

Given:

  • In an isosceles triangle the base angle are equal. The vertex angle is 14°.

Find:

  • What are the base angle of the triangle.

Using Angle sum property:

{\sf{\underline{\boxed{\red{\sf{ Sum \: of \: all \: three \: triangles = 180°}}}}}}

Calculations:

  • Let x be the base angles and the common variable to this question.

\sf{x + x + 14 = 180}

\sf{2x + 14 = 180}

\sf{2x = 180 - 14}

\sf{2x = 166}

\sf{x= 166 ÷ 2}

{\sf{\underline{\boxed{\red{\sf{x = 83° }}}}}}

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