In an isosceles triangle, the base angles are equal. The vertex angle is 40°. What are the base angles
of the triangle?
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Since the sum of all angels of a triangles =180
Let the base angles be 'x'
Therefore,
x+x+40=180
2x=180-40
2x=140
X= 140/2
x = 70
Hence the base angles of the triangle are 70, 70
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