Math, asked by Anonymous, 6 months ago

In an isosceles triangle, the base angles are equal. The vertex angle is 40°. What are the base angles of the triangle?​

Answers

Answered by Anonymous
15

Answer:

Let the base angles be x

Therefore,

x+x+40=180⁰

2x+40=180⁰

2x=180 ⁰ −40

2x=140⁰

x=70 Hence,

The base angles of the triangle are 70⁰,70⁰

Answered by ItzNavLoey
30

\huge\boxed{\fcolorbox{red}{yellow}{Solution:-}}

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\large\rm{Let ~the~ base ~angle~ be~ x}

By the condition

\rm{➝~x ~+ ~x~ +~ 40 ~= ~180°}

\rm{➝~2x ~+~ 40 ~= ~180°}

\rm{➝~2x ~= ~180~ - ~40}

\rm{➝~2x~ =~ 140}

\rm{➝~x~ = ~{\dfrac{140}{2}}}

\rm{➝~x ~=~ 70}

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