Question

in an isosceles triangle the base angles are equal the vertex angle is 40 degree water base angle of the triangle remember the sum of 3 angles of a triangle is 180 degree

Answer 1

Since the sum of all angels of a triangles =180
Let the base angles be 'x'
Therefore,
x+x+40=180
2x=180-40
2x=140
X= 140/2
x = 70
Hence the base angles of the triangle are 70, 70

Answer 2

The base angle of the triangle is 70°.

Step-by-step explanation:

We are given that in an isosceles triangle the base angles are equal and the vertex angle is 40 degrees.

We have to calculate the base angle.

Let the base angle be $x$.

Considering an isosceles triangle $\triangle$ABC, where;

$\angle$A = vertex angle = 40°

$\angle$B = $\angle$C = Base angles = $x$

As we know that the angle sum property of the triangle says: The sum of all angles of the triangle is equal to 180°.

So, $\angle$A + $\angle$B + $\angle$C = 180°

      40° + $x$ + $x$ = 180°

        $2x$ = 180° - 40°

        $2x$ = 140°

         $x =\frac{140\°}{2}$ = 70°

Hence, the base angle of an isosceles triangle is 70°.