In an isosceles triangle, the base angles are equal. The vertex angle is 40 degree. What are the base angles of the triangle? (Remember that the sum of three angles of a triangle is 180 degree.)
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Let the base angle of the triangle be x.
Given, A = 40Degree, B = C
➡️Since, a+b+c = 180degree.
➡️40degree + X + X = 180degree.
➡️40 + 2X = 180degree.
➡️2X = 180degree ➖ 40degree
➡️2X = 140degree
➡️X = 140/2
➡️X = 70degree
Thus the base angles of the isoceles triangle are 70degree each.Your Answer:-
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Answer:
Let the base angle of the triangle be x.
Given, A = 40Degree, B = C
➡️Since, a+b+c = 180degree.
➡️40degree + X + X = 180degree.
➡️40 + 2X = 180degree.
➡️2X = 180degree ➖ 40degree
➡️2X = 140degree
➡️X = 140/2
➡️X = 70degree
Thus the base angles of the isoceles triangle are 70degree each
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