Question

in an isosceles triangle the base angles are equal, the vertex angle 48° what are the base angle of the triangle. समद्विबाहु त्रिभुज में आधार कोण बराबर हैं, यदि उसका शीर्ष कोण 48° है ,तो आधार कोण क्या होगा? * 2 points 61° 63° 65° 66°​

Answer 1

Answer:

Vertex Angle = 48°

Step-by-step explanation:

Let the base angle be x.

According to the question,

2x+48° = 180°(Angle Sum Property)

2x = 180°- 48°

2x = 132°

x = 132/2

x = 66°