In an isosceles triangle,the base angles are equal.The vertex angle is 50°.Find the base angle.
Answers
Answered by
1
❤❤Here is your answer ✌ ✌
we know that sum of triangle is 180.
in isosceles triangle 2 angles are equal.
let equal angle be -x
X+X+50°=180°
2X=180°-50°
2X=130°
X=65°
so hence equal angles(base) are 65°
we know that sum of triangle is 180.
in isosceles triangle 2 angles are equal.
let equal angle be -x
X+X+50°=180°
2X=180°-50°
2X=130°
X=65°
so hence equal angles(base) are 65°
Answered by
0
let the base angle be x
if we take a triangle ABC, with AC=AB,
the angleC=angle B
therefore,
angleA + angleB + angleC = 180. (angle sum property of a triangle)
50 + x + x = 180
50 + 2x = 180
x = 65
if we take a triangle ABC, with AC=AB,
the angleC=angle B
therefore,
angleA + angleB + angleC = 180. (angle sum property of a triangle)
50 + x + x = 180
50 + 2x = 180
x = 65
Similar questions
English,
7 months ago
Hindi,
7 months ago
English,
1 year ago
Social Sciences,
1 year ago
Math,
1 year ago