In an isosceles triangle the base angles are equal. The vertex angles is 15 degree more than each of the base angles. Find the measure of the angles of the triangle
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sum of all angles of a triangle =180
let both base angles =x
then vertex angle=x+15
so x+x+x+15=180
3x+15=180
x+5=60
so x=55
so both base angles=55
vertex angle=55+15=70
let both base angles =x
then vertex angle=x+15
so x+x+x+15=180
3x+15=180
x+5=60
so x=55
so both base angles=55
vertex angle=55+15=70
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