In an isosceles triangle,the base is twice as larger as vertex angle.find the angles of the triangle. With process fast.
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LET vertex angles be x
Then, Base angles will be 2x and 2x
SUM OF ANGLES OF TRIANGLE IS 180°.
Therefore,
2x + 2x + x = 180°
5x = 180°
=> x = 36°
ANSWER =
VERTEX ANGLE = 36°
BASE ANGLES ARE EQUAL TO = 36° × 2
= 72° & 72°
Then, Base angles will be 2x and 2x
SUM OF ANGLES OF TRIANGLE IS 180°.
Therefore,
2x + 2x + x = 180°
5x = 180°
=> x = 36°
ANSWER =
VERTEX ANGLE = 36°
BASE ANGLES ARE EQUAL TO = 36° × 2
= 72° & 72°
how
The answer is 36,72,72
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