in an isosceles triangle the equal sides exceed twice the unequal side by 2cm. if the perimeter of the triangle is 34cm, find the lengths of its sides.
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Answered by
21
Let the unequal side be a cm
Length of each equal side = 2a + 2 cm
Perimeter = 2 ( Length of equal side) + Length of unequal side
=> 34 = 2 ( 2a + 2) + a
=> 34 = 4a + 4 + a
=> 30 = 5a
=> a = 6
First side = 2a + 2 = 2 × 6 + 2 = 14 cm
Second side = 2a + 2 = 2× 6 + 2 = 14 cm
Third side = a = 6 cm
Length of each equal side = 2a + 2 cm
Perimeter = 2 ( Length of equal side) + Length of unequal side
=> 34 = 2 ( 2a + 2) + a
=> 34 = 4a + 4 + a
=> 30 = 5a
=> a = 6
First side = 2a + 2 = 2 × 6 + 2 = 14 cm
Second side = 2a + 2 = 2× 6 + 2 = 14 cm
Third side = a = 6 cm
kunja77:
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in a regular polygon, each interior angle is thrice the exterior angle. find the number of sides of the polygon
can u pls answer this one tooo
Answered by
6
Let the unequal side be x cm.
Then equal sides are 2x+2.
perimeter of triangle=34cm
2x+2+2x+2+x=34
5x+4=34
5x=34-4
5x=30
x=30/5
=6
so unequal side=6cm
equal sides=2×6+2
12+2=14.
HOPE THE ANSWER HELPS YOU. PLS PLS MARK THE ANSWER AS BRAINLIEST ANSWER.
Then equal sides are 2x+2.
perimeter of triangle=34cm
2x+2+2x+2+x=34
5x+4=34
5x=34-4
5x=30
x=30/5
=6
so unequal side=6cm
equal sides=2×6+2
12+2=14.
HOPE THE ANSWER HELPS YOU. PLS PLS MARK THE ANSWER AS BRAINLIEST ANSWER.
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