Question

In an isosceles triangle ,the length of the equal exceeds that of the base by 4.5 cm.the perimeter of the triangle is 34.5 cm.find the length of the sides of the triangle

Answer 1

Given,
base of a triangle=4.5 cm
perimeter of a triangle =34.5 cm

A/Q
length of the two side be x
x+x+4.5 = 34.5 cm
2x+4.5 = 34.5 cm
2x = 34.5 - 4.5
2x = 30cm
x = 30 cm ÷ 2
x = 15 cm

for check
put the value of x = 15 cm
x+x+ 4.5 cm
15 + 15 + 4.5 cm = 34.5 cm

Answer 2

two sides are equal
let base of triangle=x
thus equal sides are [x+4.5]cm each
now perimeter=x+x+4.5+x+4.5=3x+9
34.5=3x+9
3x=25.5
x=25.5÷3
x=8.5
so sides of triangle are 8.5cm
8.5+4.5=13cm and 13cm