Question

In an isosceles triangle ,the sum of two adjacent non-equal sides is 15 unit and the sum of the two equal sides is 16 unit .Find the sides.​

Answer 1

Answer:

let x be one side,y,y be equal sides

x+y= 15

y+y= 16

2y=16

y=8

x= 7

the sides are 7,8,8

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Answer 2

Answer:

The Sides are of 8unit , 8unit and 7 unit

Step-by-step explanation:

Let The sides be x , y and z & Let x and y be equal side:-

( x = y)

NOW:-

'The Sum Of Two Aadjacent non-Equal Sides Is 15 unit'

$x + z = 15$

ALSO:-

The Sum Of Equal Sides is 16 unit:-

$x + y = 16 \\ = )x + x = 16 \: \: (x = y) \\ = )2x = 16 \\ = )x = 8$

Thus The Sides are:-

• x = 8 unit
• y = x = 8 unit
• z =)x + z = 15

=)8 + z = 18

=) z = 7

Hope it helped