Question

In an isosceles triangle the vertcal angle is thrice of either base angle (let the base angle be a in degree)

Answer 1

Ok but what's the question here???????????

Answer 2

Let ABC be an Isosceles Triangle , Then

According to question , Base Angle (B) is a°

Angle B = Angle C [ Property of an Isosceles Triangle]

=> a° = Angle C

It is also given that the Vertical Angle (A) is thrice of the base Angle ,

So , the Vertical Angle (A) = 3 x Angle B

=> 3 x a° => 3a°

Now , Angle A + Angle B + Angle C = 180°

[ Sum of the angles of a ∆ is 180° ]

3a° + a° + a° = 180°

=> 5a° = 180°

=> a° = 180°/5

=> a° = 36°

So , Angle A = 3 x a => 3 x 36° => 108°

also , Angle B = a => 36°

and Angle C = a => 36°

Hope it helped you...