Question

In an isosceles triangle, the vertex anglc is 48º. What are the base angle of that triangle?
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Answer 1

given -vertex angle is 48°

to find-base angles

solution-

let LA and LC base angles

LA+LB+LC=180( all angle of triangle are of 180°)

base angle of isosceles triangle are equal

so we can say that

2LA+LB=180

2LA+48=180°

2LA=180-48

2LA=132

LA=132/2

LA=LC=66

hence ,base angles are 66°

Thanks

hope its helpful