In an isosceles triangle the vertex angle is 40. What are the other base angles
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let an isosceles triangle ABC
A+B+C=180
let the vertex angle be A=40
we know that angles opposite to equal sides are equal
B=C
A+B+C=180
40+B+C =180
40+2B=180
2B=140
B =70
measure of base angles will be 70 degree
A+B+C=180
let the vertex angle be A=40
we know that angles opposite to equal sides are equal
B=C
A+B+C=180
40+B+C =180
40+2B=180
2B=140
B =70
measure of base angles will be 70 degree
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