in an isosceles triangle the vertex angle is 50 degree what are the base angles of the triangle
Answers
Answered by
290
let the angle be x
50+x+x=180 (ASP)
50+2x=180
2x=180-50
2x=130
x=130/2
x=65
50+x+x=180 (ASP)
50+2x=180
2x=180-50
2x=130
x=130/2
x=65
Answered by
135
Hey mate! Here is your answer:-
Since it is an isosceles triangle
Base angles would be equal.
So,let the required angle be x
By Angle Sum Property of Triangle
angle A+x+x=180°
50+2x=180°
2x=130°
x=130/2°
x=65°
Therefore required angles are 65° each.
Hope it helps you...
plz mark as brainliest...
Since it is an isosceles triangle
Base angles would be equal.
So,let the required angle be x
By Angle Sum Property of Triangle
angle A+x+x=180°
50+2x=180°
2x=130°
x=130/2°
x=65°
Therefore required angles are 65° each.
Hope it helps you...
plz mark as brainliest...
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