Math, asked by sparshdwivedi806, 6 months ago

In an isosceles triangle ,the vertex angle is 50°.What are the base angles of the triangle .Solve these question as equation​

Answers

Answered by pandyemahendra1
1

Step-by-step explanation:

As we know that the base angle of an isosceles triangle are always equal and sum of interior angles of a triangle is 180°.

Let the base angles of the isosceles triangle be x° each.

∴x+x+50°=180°

⇒2x=180°−50°

⇒x=

2

130°

=65°

Hence the base angles will be of 65° each.

Answered By nitya

Answered by EnchantedBoy
0

Answer:

65°

Step-by-step explanation:

Since,

It is an isosceles triangle

Base angles would be equal

So,

let the required angle be x

By Angle sum property of Triangle

angle A+x+x=180°

50+2x=180°

2x=130°

x=130°/2

x=65°

Therefore,

required angles are 65° each.

MARK ME BRAINLIST....

Similar questions