in an isosceles triangle, the vertex angle is 50°. what are the base angles of the triangle?
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As it is an isosceles triangle, the base angles (the angles opposite to equal sides) must be equal. So each angle will be of 65° each.
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the vertex angle is 50°
so sum of total degrees=180
so 180-50=130
130 ÷2 =65
thus, the Base angle is 65°
so sum of total degrees=180
so 180-50=130
130 ÷2 =65
thus, the Base angle is 65°
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