In an isosceles triangle the vertex angle is half base angle take the base angle b m in degree and remember sum of the angles of a triangle is 180 degrees
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given that, above triangle is an isoscelus triangle
with same base angles
let, vertex angle=a
base angles=b
also ,
vertex angle is half of the base angles
i.e.
a=1/2 *b
2a=b
but, as we know that triangles are suplimentary in measure(180°)
.'. a+b+b=180°
a+2b=180°
a+2(2a)=180°
5a=180°
a=36°
but
b=2a
b=2×36°
b=72°
Therefore, measure of vertex angle is 36°
and measure of base angles are 72° in the given isosceles triangle
Hope it helps to you☺️
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