Math, asked by wewuluwezah, 9 months ago

In an isosceles triangle the vertex angle is twice either base angle.(let the base angle be b in degrees. remember that the sum of angles of a triangle is 180 degrees

Answers

Answered by anonymo009
4

Answer:

45°, 45°, 90°

Step-by-step explanation:

Base angles = x

Vertex Angle = 2x

x + x + 2x = 180°

4x = 180°

Therefore, x = 45°

So, angles = 45°, 45°, 90°

Hope it helps you.........

Answered by IshitaAgarwal05
2

Answer:

The vertex angle = 2b = 90°

So, the given triangle is a right angled triangle.

Step-by-step explanation:

Given that, AB = AC

So, ∠ABC = ∠ACB = b [Since, angles opposite to equal sides are equal.]

Given that, ∠CAB = 2b.

We know that, The sum of the angles of a triangle = 180°

So, b+b+2b = 180°

=> 4b = 180°

=> b = 45°

So, the vertex angle = 2b = 90°

So, the given triangle is a right angled triangle.

For more explanation, refer to the figure attached.

Hope this helps.....

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