Question

in an isosceles triangle the vertex angle is twice either base angles . find the difference of the vertex and the base​

Answer 1

Answer:

45 degrees

Step-by-step explanation:

vertex angle is X so one base angle is X/2 degrees suppose

then other base angle is also X/2 so add all the angles X+ X/2+ X/2= 2X

2X = 180 degrees because of angle sum property of traingles

therefore X= 90 degree

then vertex angle is 90 and base angle is 45 degree so 90 - 45 = 45 degree

Answer 2

Answer:

45 degrees

Step-by-step explanation:

since base angles are equal we can consider both angles x

both base angles are x so double of any one will be 2x

therefore,

base angle 1 =base angle 2= x

vertex angle =x

by angle sum property,which is sum of all angles of a triangle is 180 degrees

x+x+2x =180degrees

4x=180degrees

x=45degrees