Question

in an isosceles triangle, the vertex angle is twice the sum of the
base angles. Find the angles of the triangle.​

Answer 1

Step-by-step explanation:

since, base angles of an isosceles triangle are equal.

let the base angles be x

vertex angle = 2( x + x) = 4x

A/q

x+x+4x = 180°

6x = 180°

x = 180°/6 = 30°

therefore,. base angles = 30°

vertex angle = 4×30° = 120°

Answer 2

Step-by-step explanation:

Let the one of the base angles be x

(As the base angles of an isosceles triangle are same,therefore the other base will also be x.)

Vertex angle=2x(twice of base angle)

=>x+x+2x=180°

=>4x=180°

=>x=180°/4

=>x=45°

Hence,the angles of the triangle are 45°,45° and 90°(2×45°)

Hope it helps you.....