In an isosceles triangle ,the vertical angle is 40 degree
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vertical angle=40 degree
sum of angles of a triangle=180 degree
let the other two angles be x (as the both angles r equal by theorem)
x+x+40=180
2x=140
x=70 degree
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Solution:
Let ∆A = 40
In ∆ABC
∆A+∆B+∆C = 180
40+∆B+∆B = 180
2∆B = 180-40
2∆B = 140
∆B = 140/2
∆B = 70
Hope it helps you.....
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