Question

in an isosceles triangle the Vertical angle is 55degree more than each of its base angles.. find the angles of the triangle

Answer 1

Let the base angles = x
vertical Angle = x + 55

Sum of all angles = 180

x + x + x + 55 = 180

3x + 55 = 180

3x = 180 - 55

x = 125/3

x = 41.6

x + 55 = 41.6 + 55 = 96.6

Angles are 41.6 , 41.6 and 96.6


Thanks

Answer 2

The answer is given below :

Since the given triangle is an isosceles triangle, the two base angles be considered as x° each.

Given that, the vertical angle is 55° more than the base angles. Then, the vertial angle be (x+55°).

We know that, sum of the angles of a triangle = 180°

=> x + x + (x + 55) = 180

=> 3x = 125

=> x = 125/3

So, the angles of the triangle are

125/3°, 125/3° and (55°+125/3°)

i.e., 125/3°, 125/3° and 290/3°.

Thank you for your question .