in an isoscels triangle abc the bisectors of angle b and angle c meets at apoint o.if angle a =40° then angle boc =?
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It's an isoceles triangle. so the base angles are equal. using angle sum property of triangle ABC
Let us take angleABC as x.
angleABC=angleACB(isoceles triangle)
angleABC+angleACB+angleBAC=180°
40°+x°+x°=180°
2x°=180-40
x=140/2
angle x=70°
angles B and C are bisected and produced to O
angleBOC=180°-angleOBC-angleOCB(angle sum property of triangle BOC)
angleBOC=180°-2(70/2){angular bisectors}
angleBOC=180-70
angleBOC=110°
Let us take angleABC as x.
angleABC=angleACB(isoceles triangle)
angleABC+angleACB+angleBAC=180°
40°+x°+x°=180°
2x°=180-40
x=140/2
angle x=70°
angles B and C are bisected and produced to O
angleBOC=180°-angleOBC-angleOCB(angle sum property of triangle BOC)
angleBOC=180°-2(70/2){angular bisectors}
angleBOC=180-70
angleBOC=110°
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