in an isosclese triangle ABC, if ac=bc and AB square = 2AC square then finc c
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Given: AC = BC
ABC is an isoceles triangle
AB2 = 2 AC2
To prove: ABC is a right triangle
Proof: For ABC to be a right triangle, it should satify pythagoras theorem
i.e AB2 = AC2 + BC2
Now, AC = BC (given)
On substitution, we find
AB2 = 2 AC2, which is true according to the question.
So, the given sides form pythorian triplets.
Hence ABC to be a right triangle right angled at C.
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