Question

In an isosocles triangle ABC, if AB = AC = 25 cm.
and BC - 14 cm, then the measure of altitude from
A on BC is​

Answer 1

Step-by-step explanation:

by pythagoras theorem, 24cm will be the answer.

Answer 2

Answer:

The answer is 24cm

Step-by-step explanation:

Let the two equal sides be 'a' and remained side be 'b'.

AB=AC=a=25cm

BC=b=14cm

We know that,

Area of isosceles∆ABC(A)=b/4√(4a^2-b^2)

=14cm/4√(4*25cm^2-14cm*14cm)

=3.5cm*48cm

=168sq.cm

Then,

Also, We know that,

Area of any triangle(A)=1/2*base*altitude

So, let the altitude be AD and base be BC for ∆ABC

According to formula,

Area of ∆ABC=1/2*BC*AD

or,168sq.cm=1/2*14cm*AD

or,AD=168sq.cm*2/14cm

Therefore,AD=24cm