In an isothermal process bat 300k 1 mole of an ideal gas expand from a pressure 100 atm against external 50 atm then total entropy change in the process
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Answer:
Given that,
Temperature = 300 K
Weight of gas = 1 mol
Initial pressure = 100 atm
Finale pressure = 50 atm
We need to calculate the total entropy change
Using formula of entropy
In an isothermal process so the temperature will not change
Where, n = weight of gas
P₁ =initial pressure
P₂ = final pressure
R = gas constant
Put the value into the formula
The nearest option is 1.59 J/k.
Hence, The total entropy change is 1.59 J/K.
(C) is correct option.
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