Question

In an isothermal process bat 300k 1 mole of an ideal gas expand from a pressure 100 atm against external 50 atm then total entropy change in the process

Answer 1

Answer:

Given that,

Temperature = 300 K

Weight of gas = 1 mol

Initial pressure = 100 atm

Finale pressure = 50 atm

We need to calculate the total entropy change

Using formula of entropy

In an isothermal process so the temperature will not change

Where, n = weight of gas

P₁ =initial pressure

P₂ = final pressure

R = gas constant

Put the value into the formula

The nearest option is 1.59 J/k.

Hence, The total entropy change is 1.59 J/K.

(C) is correct option.

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