Question

In an isothermal process, entropy change for 1 mol of substance is expressed as
AS-
arev
T2
AS-2RIn
O AS-nRTIN
Run
P2
AS = Rin

Answer 1

Answer:

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Answer 2

Answer: For 1 mole of a substance the entropy change for isothermal process is ΔS = 2.303 R log V₂/V₁

Explanation: Entropy is a scientific concept as well as a measurable physical property, that is most commonly associated with a state of disorder, randomness, or uncertainty. The term and the concept are used in diverse fields.

In the reversible process the change in entropy of the surroundings is equal and opposite to the change in the system, so the change in entropy of the universe is zero.

For isothermal process ΔT = 0

ΔS = q/T

q = p₁v₁ ln v₂/v₁ = nRT ln v₂/v₁ ( As per ideal gas equation)

ΔS = nRT ln v₂/v₁÷ T

     = nR ln v₂/v₁

For 1 mole of a substance it will be ΔS = 2.303 R log v₂/v₁

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