Physics, asked by nishayadav40921, 10 months ago

In an n- type silicon, which of the following statements is true ? (a) Electrons are majority carries and trivalent atoms are the dopants. (b) Electrons are majority carries and pentavalent atoms are the dopants. (c ) Holes are minority carries and paentavalent atoms are the dopants. (d) Holes are minority carries and trivalent atoms are the dopants.

Answers

Answered by AnkitaSahni
1

Option B & C are correct

•When a pure semiconductor is doped by pentavalent impurity ( P , As , Sb , Bi) then four electrons out of the fivr valence electrons of impurity take part in covalent bonding , with four silicon atoms surrounding it and the fifth electron is set free.

• These impurity atoms which donate free e- for conduction are called donor impurity.

• where free e- increases very much so that is called as n - type semiconductor .

• In N type free e- are majority charge carriers and holes are minority charge carriers

so, option B & C are correct

i.e. Electrons are majority carries and pentavalent atoms are the dopants

& Holes are minority carries and paentavalent atoms are the dopants

Answered by Anonymous
0

\\Option B & C are correct

•When a pure semiconductor is doped by pentavalent impurity ( P , As , Sb , Bi) then four electrons out of the fivr valence electrons of impurity take part in covalent bonding , with four silicon atoms surrounding it and the fifth electron is set free.

• These impurity atoms which donate free e- for conduction are called donor impurity.

• where free e- increases very much so that is called as n - type semiconductor .

• In N type free e- are majority charge carriers and holes are minority charge carriers

so, option B & C are correct

i.e. Electrons are majority carries and pentavalent atoms are the dopants

& Holes are minority carries and paentavalent atoms are the dopants

Answer:

Explanation:

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