Question

in an obtuse triangle the squares of sides opposite to obtuse angle is equal to the sum of square of other two sides plus twice the product of one side and the projection of other an first​

Answer 1

Answer:

less than the square on the third side

The triangle is an obtuse triangle if the sum of the squares of the smaller sides is less than the square of the largest side.

Let ABC is an obtuse triangle.

∠B=120

o

AB=5cm,BC=4cm and AC=8cm

⇒ (AC)

2

=(8)

2

=64 ---- ( 1 )

⇒ (AB)

2

+(BC)

2

=(5)

2

+(4)

2

=25+16=41 ---- ( 2 )

From ( 1 ) and ( 2 ) we can see,

⇒ (AB)

2

+(BC)

2

<(AC)

2

Hence, In an obtuse angled triangle, the sum of the squares on the sides making the obtuse angle is less than the square on the third side.

Step-by-step explanation:

please try to Mark me as brainlists please