Question

In an open circuit an electric cell of electromotive force of 1.6 V and internal resistance of 2 Ω is connected. If two resistances of 4 Ω and 10 Ω are connected in series across the two terminals of the cell, find the potential difference across each resistor ​

Answer 1

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Answer 2

Answer:

Equivalent internal resistance of parallel connection

1+2/1×2=2/3Ω

Equivalent emf of cells in parallel connection

[ 2/1] +[4/2]× 2/3= 8/3 V

Potential difference across 10Ω resistor,

10/2+2/3 ×8/3= 2.5 V