Physics, asked by brinda2765, 11 months ago

In an optical fiber, the core material has refractive index 1.6 and refractive index of clad material is 1.3. What is the value of critical angle?

Answers

Answered by VLHimavarshini
0

Explanation:

given refractive index of core(n1)=1.6

refractive index of clad(n2)=1.3

from Snells law,

n1 sin i =n2 sin r

sin c=1.3/1.6

c=54.34°

Answered by mousmikumarisl
0

Answer:

the correct answer is 54.34 degree

Explanation:

Given Data :

  • The refractive index of core = 1.6
  • The refractive index of clad material = 1.3

Formula to be used :

Snell's law:

(n1 sin i = n2 sin r)

sin i / sin r = 1.3/1.6

sin c = 0.8125

So, c = 54.34 degrees

  • The angle of incidence, for which the angle of refraction is 90°, is the critical angle. Light changes direction and bends toward the normal if it enters a denser medium from one that is relatively more uncommon.
  • A flexible, transparent fibre known as an optical fibre is created by pulling glass or plastic to a diameter just a hair's width thicker. It is non-flammable and uses less power.
  • Total internal reflection is the basis for how the optical fibre functions.
  • Large amounts of data can be transmitted using light rays, but there is a drawback: they move in straight lines.
  • So, exploiting this advantage will be time-consuming unless we have a long, straight line without any bends.
  • . Instead, all light beams are bent inward by the optical cables' unique architecture (using TIR)

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