Question

In an optical fibre, the core material has refractive index 1.6 and refractive index of cladding material is 1.3. Calculate the critical angle and angle of acceptance cone.

Answer 1

Dear Student,

◆ Answer -

c = 54.34°

α = 68.86°

● Explanation -

Critical angle is calculated as -

sinc = n2/n1

sinc = 1.3/1.6

sinc = 0.8125

c = arcsin(0.8125)

c = 54.34°

Angle of acceptance ia given by -

sinα = √(n1^2-n2^2) / n0

sinα = √(1.6^2-1.3^2) / 1

sinα = √(2.56-1.69)

sinα = √(0.87)

sinα = 0.9327

α = arcsin(0.9327)

α = 68.86°

Thanks dear...

Answer 2

Answer:

◆ Answer -

c = 54.34°

α = 68.86°

● Explanation -

Critical angle is calculated as -

sinc = n2/n1

sinc = 1.3/1.6

sinc = 0.8125

c = arcsin(0.8125)

c = 54.34°

Angle of acceptance ia given by -

sinα = √(n1^2-n2^2) / n0

sinα = √(1.6^2-1.3^2) / 1

sinα = √(2.56-1.69)

sinα = √(0.87)

sinα = 0.9327

α = arcsin(0.9327)

α = 68.86°