Question

In an orbit if the time of revolution of a satellite is T, then PE is proportional to

Answer 1

aswer is in pic i hope it helps

Answer 2

In an orbit, if the time of the revolution of a satellite is $T$, then $PE$is proportional to $T^{-\frac{2}{3} }$.

Explanation:

We know that $PE=\frac{-GMm}{R}$,

⇒$R=\frac{-GMm}{PE}$.

⇒$R{\propto}\frac{1}{PE}$

According to Kepler's law,

$T^{2} {\propto}R^{3}$

 $R{\propto}T^{\frac{2}{3} }$

$\frac{1}{PE}{\propto}T^{\frac{2}{3} }$

$PE{\propto}T^{\frac{-2}{3} }$