Question

In an orchard, 1/3 part is apple trees,1/4 part is pear trees and the rest are orange trees.What part of the orchard is orange trees?​

Answer 1

Answer:

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Answer 2

Answer:

lettotalnumberoftrees=x

lettotalnumberoftrees=xthenbananatrees=148

lettotalnumberoftrees=xthenbananatrees=148x−(

lettotalnumberoftrees=xthenbananatrees=148x−( 5

lettotalnumberoftrees=xthenbananatrees=148x−( 5x

lettotalnumberoftrees=xthenbananatrees=148x−( 5x

lettotalnumberoftrees=xthenbananatrees=148x−( 5x )−(

lettotalnumberoftrees=xthenbananatrees=148x−( 5x )−( 13

lettotalnumberoftrees=xthenbananatrees=148x−( 5x )−( 133x

lettotalnumberoftrees=xthenbananatrees=148x−( 5x )−( 133x

lettotalnumberoftrees=xthenbananatrees=148x−( 5x )−( 133x )=148

lettotalnumberoftrees=xthenbananatrees=148x−( 5x )−( 133x )=148(

lettotalnumberoftrees=xthenbananatrees=148x−( 5x )−( 133x )=148( 65

lettotalnumberoftrees=xthenbananatrees=148x−( 5x )−( 133x )=148( 6565x−13x−15x

lettotalnumberoftrees=xthenbananatrees=148x−( 5x )−( 133x )=148( 6565x−13x−15x

lettotalnumberoftrees=xthenbananatrees=148x−( 5x )−( 133x )=148( 6565x−13x−15x )=148

lettotalnumberoftrees=xthenbananatrees=148x−( 5x )−( 133x )=148( 6565x−13x−15x )=148∴x=(

lettotalnumberoftrees=xthenbananatrees=148x−( 5x )−( 133x )=148( 6565x−13x−15x )=148∴x=( 37

lettotalnumberoftrees=xthenbananatrees=148x−( 5x )−( 133x )=148( 6565x−13x−15x )=148∴x=( 37148×65

lettotalnumberoftrees=xthenbananatrees=148x−( 5x )−( 133x )=148( 6565x−13x−15x )=148∴x=( 37148×65

lettotalnumberoftrees=xthenbananatrees=148x−( 5x )−( 133x )=148( 6565x−13x−15x )=148∴x=( 37148×65 )=260