Question

In an orchard with m orange tree. every tree produced p orange. some oranges were lost due to a hailstorm and 3/4mp oranges remained. The percentage of oranges lost was..?​

Answer 1

Answer:

We are given that in an orchard, 1/5 are orange trees, 3/13 are mango trees and the rest are banana trees.

And the banana trees are 148 in number.

Let the total number of trees be x.

So, the number of Orange trees = \frac{1}{5} \times x

5

1

×x = \frac{x}{5}

5

x

Number of mango trees = \frac{3}{13} \times x

13

3

×x = \frac{3x}{13}

13

3x

Now, the fraction of banana trees in an orchard = 1 - \frac{1}{5} -\frac{3}{13}1−

5

1

−

13

3

= \frac{37}{65}

65

37

So, Number of banana trees = \frac{37}{65}\times x

65

37

×x , which means;

148 = \frac{37x}{65}

65

37x

x = \frac{148 \times 65}{37}

37

148×65

= 260

Hence, the total number of trees in an orchard is 260.