Question

In an organic compound C=54.3%, H=9.0%
and O=36.7%. if Vapour density of this
compound is 44. Find out molecular
formula of this compound.​

Answer 1

Answer:

answr

search

What would you like to ask?

11th

Chemistry

Organic Chemistry - Some Basic Principles and Techniques

Qualitative Analysis of Organic Compounds

FInd the molecular formula ...

CHEMISTRY

avatar

Asked on December 26, 2019 by

Md Gorawala

FInd the molecular formula of the compound having 54.5% Carbon, 9.23% Hydrogen. (Vapour density=44g/l, Molar mass=88 g/mol)

MEDIUM

Share

Study later

ANSWER

The compound has 54.5% Carbon, 9.23% Hydrogen. The remaining is Oxygen.

100 g of the compound will have 54.5 g C, 9.23 g H and 100−54.5−9.23=36.27 g O.

The atomic masses of C, H and O are 12 g/mol, 1 g/mol and 16 g/mol respectively.

The number of moles of C=

12 g/mol

54.5 g

=4.54 mol.

The number of moles of H=

1 g/mol

9.23 g

=9.23 mol.

The number of moles of O=

16 g/mol

36.27 g

=2.27 mol.

Mole ratio C:H:O=4.54:9.23:2.27=2:4:1

The empirical formula of the compound is C

2

H

4

O

The empirical formula mass =2(12)+4(1)+16=44 g/molMolar mass of the compound is 88 g/mol. It is twice the empirical formula mass of 44 g/mol.

The molecular formula of the compound is C

4

H

8

O

2