Question

in an organic compound C,H&N are present in the ratio of 9:1 :3:5 by weight. Find the emperical formula ?​

Answer 1

Explanation:

ANSWER

Find ratio of atoms, empirical formula, n and molecular formula.

Given, C:H:N=9:1:3.5 (ratio of weights)

Mol.wt.=108

Element Ratio of wt. Ratio of atoms Simplest ratio

C 9 9/12=0.75 0.75/0.25=3

H 1 1/1=1 1/0.25=4

N 3.5 3.5/14=0.25 0.25/0.25=1

∴ Empirical formula =C

3

H

4

N

Empirical formula wt.

=12×3+1×4+14=54

n=

empirical formula wt.

mol.wt.

=

54

108

=2

Molecular formula = empirical formula ×n

=2(C

3

H

4

N)

=C

6

H

8

N

2