Question

In an organic compound it is found that it contains 12 % carbon 27% oxygen andreas hydrogen calculate empirical formula

Answer 1

Hello!

In an organic compound it is found that it contains 12 % carbon 27% oxygen andreas hydrogen calculate empirical formula

data:

Carbon (C) ≈ 12 a.m.u (g/mol)

Oxygen (O) ≈ 16 a.m.u (g/mol)

We use the amount in grams (mass ratio) based on the composition of the elements, see: (in 100g solution)

C: 12 % = 12 g

O: 27 % = 27 g

The values ​​(in g) will be converted into quantity of substance (number of mols), dividing by molecular weight (g / mol) each of the values, we will see:

$C: \dfrac{12\:\diagup\!\!\!\!\!g}{12\:\diagup\!\!\!\!\!g/mol} = 1\:mol$

$O: \dfrac{27\:\diagup\!\!\!\!\!g}{16\:\diagup\!\!\!\!\!g/mol} = 1.6875\:mol$

We realize that the values ​​found above, some are not integers, so we divide these values ​​by the smallest of them, so that the proportion does not change, let's see:

$C: \dfrac{1}{1}\to\:\:\boxed{C = 1}$

$O: \dfrac{1.6875}{1}\to\:\:\boxed{O = 1.6875}$

convert number of atomic radio into whole number    

3*(1 : 1.6875) =  

= 3 : 5  ← whole number of atomic radio  

C = 3

O ≈ 5

Thus, the minimum or Empirical Formula (E.F) found for the compound will be:

$\boxed{C_3O_5}\Longleftarrow(Empirical\:Formula)\end{array}}\qquad\checkmark$

Answer:

C3O5

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I Hope this helps, greetings ... Dexteright02! =)