Question

In an ornament weighting 16 gm . the ratio of pure gold and the other metal is 7:1, What is the quantity of pure gold in the ornament?
Options
a 12 gm
b 8 gm
c 7 gm
d 14 gm​

Answer 1

14 grams is the quantity of pure gold is in the ornament when an ornament weighting is 16 gram and the ratio is 7:1.

Given that,

In an ornament weighting is 16 gram. Pure gold is in a 7:1 ratio with the other metal.

We have to find what is the quantity of pure gold in the ornament.

We know that,

Pure gold is in a 7:1 ratio with the other metal.

The pure gold quantity is of 7 and the metal is 1

The ornament weight is 16 gm

Then,

Weight of pure gold is 7 × $\frac{16}{7+1}$ = 7 × $\frac{16}{8}$ = 7×2 = 14 grams

Therefore, 14 grams is the quantity of pure gold is in the ornament.

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Answer 2

Answer:

The Quantity of pure gold is 14 gm

Step-by-step explanation:

Let the ratio of pure gold be 7x

Let the ratio of other metal be one 1x

According to the question ,

7x + 1x = 16

8x = 16

x = 16/8

x = 2

So , The value of x is 2 ..

Now ,

Quantity of pure gold = 7(2)

14 gm.