Question

In an ornament weighting 16 gm. the ratio of pure gold and the other metal is 7:1. What is the quantity of pure gold in the ornament?
Answer 14 gm
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Answer 1

Answer:

total weight = 16gm

ratio = 7 : 1

Amount of pure gold =

$\frac{7}{8 } \times 16$

= 7 × 2

= 14

Answer 2

Answer:

14gm

Step-by-step explanation:

7:1.

7/8×16=14gm