Question

In an orthogonal turning of 100 mm diameter bar with uncut thickness 5 mm & rake angle15%. The process having cutting force 1200N and thrust force 250N. Calculate coefficientof friction if chip thickness is 7mm. Also calculate shear angle.0.5, 40.240.7.26.560.33, 16.470.24, 33.42​

Answer 1

Explanation:

It is the ratio of cutting power by material removal rate.

Where,

FC = Main cutting Force, VC = Cutting Velocity, t1 = uncut chip thickness, b = width of cut.

Calculation:

Given:

For orthogonal cutting:

Depth of cut = width of cut ⇒ d = b = 4 mm = 4 × 10-3 m

Specific cutting energy = 1 × 109 J/m3

Feed = uncut chip thickness ⇒ f = t1 = 0.25 mm/rev.

⇒ t1 = 0.25 × 10-3 m;

Specific Cutting Energy:

⇒ Fc = 1000

⇒ FC = 1000 N