In an oscillating L-C circuit the maximum charge on the capacitor is Q. What will be the charge on the plate of the capacitor, when energy stored in magnetic field and electric field are equal? choose the correct option from the given options.
(A) Q/3
(B) Q/√2
(C) Q
(D) Q/2
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Answer:
b) Q/√2
Explanation:
In parallel resonance L-C circuit, energy keeps moving from L and C every half cycle, and no current is drawn from the supply. Total energy stored in the condenser is transferred to the inducer and then returned to the condenser again, and the cycle continues. The condenser storage is in the electrical field, while the inductor stores the magnetic field energy.
Therefore, for a given energy. which is stored in the capacitor if the energy on the charge on the capacitor is halved it will be Q/√2.
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