Question

In an oxidation-reduction reaction, MnO,
ion is converted to Mn?. What is the number
of equivalents of KMnO,(mol. wt = 158)
present in 250 ml of 0.04 M KMnO4 solution?​

Answer 1

Answer:

0.05

Explanation:

change in oxidation number =(+7)-(+2)

= 5

.•. Normality of solution = 5*0.04

= 0.20N

Volume = 250mL

.•. Number of equivalents KMnO4 =

=0.20*250/1000

= 0.05